Given m A = 20 kg., m B = 10 kg, m C = 20 kg, between B and C µ 2 = 0.3 and between C and ground µ 3 = 0.1. The least horizontal force F to start the motion of any part of the system of three blocks resting upon one another as shown in figure is (g = 10 m/s 2 ) –

Text Solution
Verified by ExpertsThe correct answer is:
D
Limiting friction between A and B = 60 N
Limiting friction between B and C = 90 N
Limiting friction between C and ground = 50 N
Since limiting friction is least between C and ground, slipping will occur at first between C and ground. This will occur when F = 50 N
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
The system shown in the figure is in equilibrium. The maximum value of W, so that the maximum value…
A mass of 2 kg is placed on a trolley of 20 kg sliding on a smooth surface. The coefficient of fric…
Blocks of mass m and block B of mass 2m are placed on a fixed triangular wedge by means of massless…
An insect crawls up a hemispherical surface very slowly. The coefficient of friction between the in…
A body of mass m is kept on a rough horizontal surface of friction coefficient μ μ . A force is app…
All surface are frictionless and pulley & strings are light. Acceleration of block of mass 'm' is -