A 25 Kg solid sphere with a 20 cm radius is suspended by a vertical wire. A torque of 0.10 N-m is required to rotate the sphere through an angle of 1.0 rad and then maintain the orientation. If the sphere is then released, its period of the oscillations will be:
Text Solution
Verified by ExpertsThe correct answer is:
D
τ τ = - k θ θ for torsional harmonic motion.
0.1 = - k (1.0) where k is torsional constant of the wire.
k = 
T = 2 π π 
= 2 π π 
= 4 π π second
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