Each of the two strings of length 51.6 cm and 49.1 cm are tensioned separately by 20 N force. Mass per unit length of both the strings is same and equal to 
. When both the strings vibrate simultaneously, the number of beats is
Text Solution
Verified by ExpertsThe correct answer is:
B
Frequency of first string
Similarly, frequency of second string
Number of beats 
difference of frequency of two strings.
beats
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