Home Physics Simple Harmonic Motion (Oscillations) JEE Main 2025 A block of mass 2 kg is attached to one end …
Physics Simple Harmonic Motion (Oscillations) JEE Main 2025 MCQ (Single Correct)

A block of mass 2 kg is attached to one end of a massless spring whose other end is fixed at a wall. The spring-mass system moves on a frictionless horizontal table. The spring's natural length is 2 m and spring constant is . The block is pushed such that the length of the spring becomes 1 m and then released. At distance from the wall, the speed of the block will be

A

B

C
D

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Text Solution

Verified by Experts
The correct answer is:
A

Natural length of the spring: 2 meters
Initial compression of the spring : 1 meter

Final compression of the spring when the block is at distance meters

Solution:

To find the block's speed, we'll use energy conservation. Initially, the spring's potential energy is fully converted to kinetic energy and spring potential energy at the new position .

Conservation of Energy:

Initial kinetic energy ( ) is 0 since the block starts from rest.

Initial potential energy ( ) due to spring compression is .

At a distance , the kinetic energy ( ) is and the potential energy ( ) is .

Rearrange to find :

Substitute known values:

Simplify and solve for :

Finally, take the square root to find :

Therefore, the speed of the block at distance from the wall is given by the expression above.

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