A particle of charge
and mass
is present in a strong magnetic field of 6.28 T. The particle is then fired perpendicular to magnetic field. The time required for the particle to return to original location for the first time is ______s. 
Text Solution
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To solve this problem, note that when a charged particle with mass m and charge q is fired perpendicular to a magnetic field of strength B, it undergoes uniform circular motion. The period (time to complete one full circle) is given by:

Here's how to calculate it step by step:
Convert the given quantities to SI units:
Charge:
Mass:
Magnetic field: 
Write down the period formula:

Substitute the values:

Notice that
, which cancels with the given magnetic field value, simplifying the expression:

Simplify the fraction:

Thus, the time required for the particle to return to its original location is: 
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