Physics Thermometry, Thermal Expansion and Calorimetry JEE Main 2025 - ( Thermal Properties of Matter ) MCQ (Single Correct)

Two wires A and B are made of same material having ratio of lengths and their diameters ratio . If both the wires are stretched using same force, what would be the ratio of their respective elongations?

A
3: 4
B
1: 12
C
1: 3
D
1 : 6

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Text Solution

Verified by Experts
The correct answer is:
B

Given:

The ratio of lengths:
The ratio of diameters:
Both wires are subject to the same stretching force, and since they are made of the same material, their Young's modulus is the same.

The elongation ( ) of a wire subject to a force is given by:
where is the force applied, is the original length, is the cross-sectional area, and is Young's modulus.

For wires and :

Since and , the ratio of their elongations becomes:

The cross-sectional area is a function of diameter, . Therefore,

Substituting these into the elongation ratio:

Substitute the given ratios:

Thus, the ratio of the elongations of wires and is .

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