Student A and Student B used two screw gauges of equal pitch and 100 equal circular divisions to measure the radius of a given wire. The actual value of the radius of the wire is 0.322cm. The absolute value of the difference between the final circular scale readings observed by the students A and B is [Figure shows position of reference 'O' when jaws of screw gauge are closed] Given pitch =0.1cm.
Text Solution
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(13)
For
Read ing= MSR + CSR+ Error
0.322 = 0.300 + CSR + 5 × LC
0.322 = 0.300 + CSR + 0.005
CSR = 0.017
For B
Reading = MSR + CSR+ Error 0.322 = 0.200 + CSR + 0.092
CSR = 0.030
Difference = 0.030 − 0.017 = 0.013 cm
Division on circular scale 
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