Published by:
CGP EDU Academic Team
Published on: September 12, 2026
The vernier constant of Vernier callipers is 0.1 mm and it has zero error of (-0.05) cm. While measuring diameter of a sphere, the main scale reading is 1.7 cm and coinciding vernier division is 5. The corrected diameter will be_____x 10 -2 cm.
Text Solution
Verified by ExpertsThe correct answer is:
180
(180)
Measured diameter = MSR + VSR x VC
= 1.7 + 0.01 x 5
= 1.75
Corrected = Measured - Error
= 1.75 -(-0.05)
= 1.80cm
= 180 x 10 -2 cm
180
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
If Z = , then the relative error in Z will be :
A sliver wire has mass (0.6±0.006)g, radius (0,5 ± 0.005) mm and length (4 ± 0.04) cm. The maximum …
For where 'a' is a constant If percentage error in measurement of 'x' and 'y' are 4% and 12%, resp…
The one division of main scale of vernier callipers reads 1 mm and 10 divisions of Vernier scale is…
The density of a solid metal sphere is determined by measuring its mass and its diameter. The maxim…
NUMERIC RESPONSE
The minimum uncertainty in the speed of an electron in an one-dimensional region o…