The vernier constant of Vernier callipers is 0.1 mm and it has zero error of (-0.05) cm. While measuring diameter of a sphere, the main scale reading is 1.7 cm and coinciding vernier division is 5. The corrected diameter will be_____x 10 -2 cm.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(180)
Measured diameter = MSR + VSR x VC
= 1.7 + 0.01 x 5
= 1.75
Corrected = Measured - Error
= 1.75 -(-0.05)
= 1.80cm
= 180 x 10 -2 cm
180
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