Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A short bar magnet placed with its axis at
with an external field of 800 Gauss, experiences a torque of
. The work done in moving it from most stable to most unstable position is
. The value of
is
.
Text Solution
Verified by ExpertsThe correct answer is:
64
(64)
For a magnetic dipole in an external field, torque is 
At

Work done from most stable (aligned,
) to most unstable (anti-aligned,
) position equals the change in potential energy:

Therefore, 
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