A beam of plane polarized light falls normally on a polarizer of cross sectional area 
. Flux of energy of incident ray in 10 –3 W. The polarizer rotates with an angular frequency of 31.4 rad/sec . The energy of light passing through the polarizer per revolution will be
Text Solution
Verified by ExpertsThe correct answer is:
A
Using Matus law, 
As here polariser is rotating i.e. all the values of θ θ are possible.
On integration we get 
where 
∴ ∴ 
and Time period 
∴ ∴ Energy of light passing through the polariser per revolution 
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