The figure shows elliptical orbit of a planet m about the sun S. The shaded area SCD is twice the shaded area SAB. If t 1 is the time for the planet to move from C to D and t 2 is the time to move from A to B, then:
Text Solution
Verified by ExpertsThe correct answer is:
C
Apply Kepler's law of area of planetary motion.
The line joining the sun to the planet sweeps out equal areas in equal time interval I,e, areal velocity is
constant. ,
= constant or 
or t1 = 
Given A 1 = 2A 2
∴ t 1 = 2t 2
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