A 100 kg gun fires a ball of 1 kg horizontally from a cliff of height 500 m. It falls on the ground at a distance of 400 m from the bottom of the cliff. The recoil velocity of the gun is:
(Take
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Text Solution
Verified by ExpertsThe correct answer is:
B
: Here Mass of the gun 
Mass of the ball 
Height of the cliff, 

Time taken by the ball to reach the ground is

Horizontal distance covered = ut

Where u is the velocity of the ball

According to law of conservation of linear momentum we get


-ve sign shows that the direction of recoil of the gun is opposite to that of the ball.
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