Home Physics Wave and Sound Mix Two identical tuning forks vibrating at the …
Physics Wave and Sound Mix MCQ (Single Correct)

Two identical tuning forks vibrating at the same frequency 256 Hz are kept fixed at some distance apart. A listener runs between the forks at a speed of 3.0 m/s so that he approaches one tuning fork and recedes from the other. Find the beat frequency observed by the listener. Speed of sound in air = 332 m/s.

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The correct answer is:
CHECK THE SOLUTION.

Given:
Speed of sound in air
Velocity of the observer
Velocity of the source
Frequency of the tuning forks
The apparent frequency heard by the man when he is running towards the tuning forks is
On substituting the values in the above equation, we get:

The apparent frequency heard by the man when he is running away from the tuning forks is
On substituting the values in the above equation, we get:

beats produced by them

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