What kinetic energy must a proton posses to split a deuteron H 2 whose binding energy is E b = 2.2 MeV ?
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
Sol. The splitting reaction of deuteron by a proton may be represented as
P + H 2 — → p + n + p … (1)
The energy of this reaction must be the binding energy of the deuteron. So, the threshold kinetic energy of the proton is given as
T th =
|Q|
or, T th = [(m p + m d )/m d ]E b
The proton must have energy T greater than or equal to T th . So, the energy of the proton for the required split reaction is given as
or, Q = {m d – (m p + m n )/m d )}c 2 … (2)
so, E b = |Q|
Now the binding energy of the reaction is given as
E b = [
+ (A – Z)m n – m d ]c 2 Since for H
2 , Z = 1 and A = 2. So,
E b = (m p + m n – m d )c 2 … (3)
Here m H is the mass of hydrogen atom. So, m H = m p m n and m d is the masses of neutron and H 2 atom. So, from equations (1) and (3), we get
or,

So, on putting the values, we get

Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems