A rod of mass m and length l λ fits into a hollow tube of same length and mass. The tube is rotated with an initial angular velocity ω ω 0 and the rod slips through the rough hollow surface. The angular velocity of the rod as it slips out of the tube is
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
B
There is no external torque acting on the system. Hence angular momentum remains conserved.
I 1 ω ω 1 = I 2 ω ω 2
I 1 = 2M l λ 2 /3; I 2 = [2M(2 l λ ) 2 /3] ⇒ ⇒ ω ω 2 = ω ω o /4
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