Match the column:
Column I | Column II |
(i) Angular displacement | [A] Axial vector |
(ii) Angular momentum | [B] It is directed along the axis of rotation and normal to the plane |
(iii) Torque is zero | [C] Moment of linear momentum |
(iv) In pure rolling K.E. (S) of sphere at any point is | [D] mv2 |
[E] Angular momentum is constant |
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
Ans.
(i) [A], [B]
(ii) [A], [B], [C]
(iii) [E]
(iv) [D]
Sol. All axial vectors are directed along the axis of rotation and normal to plane
For angular momentum
= 
× 
It is an axial vector
For 
= 
when 
= constants
τ = 0
For and (S) in pure rolling consist translatory and rotatory motion both.
(K.E.) total (K.E.) total = (K.E.) r + (K.E.) t
= 
I ω 2 + 
mv 2 = 
. 
mR
2 ω 2 + 
mv 2 ( ω 2 = 
)
= 
mv 2
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