A ball is projected upwards from the top of the tower with a velocity 50 ms –1 making an angle 30° with the horizontal. The height of tower is 70 m. After how many seconds the ball will strike the ground?
Text Solution
Verified by ExpertsThe correct answer is:
C
= 
70 = – (50 sin 30 C ) t + 
×10 × t 2
70 = –25 t + 5t 2 or t
2 –5t –14 = 0 
t = –2sec
or t = 7sec. (–ve time is not possible)
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