A particle starts flying in the xy-plane with a speed of 
. Initial position of the particle was the origin (0, 0) of the plane. The trajectory of the particle is represented by the equation –
Text Solution
Verified by ExpertsThe correct answer is:
A
v x = 
= 2 m/s
⇒ x = 2t …..(i)
also, v y = 
= 5x
⇒ dy = xdt = 5(2t) dt from eq. (i)
⇒ dy = 10t dt
⇒ y = 
= 5t 2 …….(ii)
From (i) and (ii)
y = 5 (x/2) 2 ⇒ y = 
x
2
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