A large parallel plate capacitor with uniform surface charge σ on the upper plate & – σ on the lower is moving with a constant speed V as shown in figure.
(i) Magnetic field between the plates is –
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Ans.
(i)
Sol. Current per unit width (J)
= 
= 
= σ V
J = σ V
B due to both plate is 
Both are upward
∴ B net = 
+ 
= μ 0 J
B Net = μ 0 σ V
(ii)
Sol. Magnetic force on upper plate area
= 
= 
f = 
force per unit area = 
= 
upward
(iii)
Sol. Electric field of the lower Plate is 
: the electric force per unit area on the pper plate as 
. Then force is downward f mag. = 
(balancing)
= 
, V = 
= c
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