Four particles of masses m, 2m, 3m and 4m are kept in sequence at the corners of a square of side a. The magnitude of gravitational force acting on a particle of mass m placed at the centre of the square will be
A
B
C
D
Zero
Text Solution
Verified by ExpertsThe correct answer is:
C
If two particles of mass 
are placed x distance apart then force of attraction 
(Let)
Now according to problem particle of mass m is placed at the centre (P) of square. Then it will experience four forces
force at point P due to particle 
Similarly, 
, 
and
Hence the net force on P
[ 
half of the diagonal of the square]
.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A body of mass rises to height from the earth's surface, where R is earth's radius. If g is accel…
In a gravitational field, at a point where the gravitational potential is zero
The gravitational field due to a mass distribution is in the x-direction. (K is a constant). Takin…
The mass of the earth is and that of the moon is . The constant of gravitation . The potential e…
The change in potential energy, when a body of mass m is raised to a height nR from the earth's sur…
The masses and radii of the earth and moon are and respectively. Their centers are distance d apa…