A pendulum is executing simple harmonic motion and its maximum kinetic energy is K 1 . If the length of the pendulum is doubled and it performs simple harmonic motion with the same amplitude as in the first case, its maximum kinetic energy is K 2 . Then:
A
K 2 = 
B
K 2 =2K 1
C
K 2 = K 1
D
K 2 = 
Text Solution
Verified by ExpertsThe correct answer is:
B
Maximum kinetic energy = 
mꞷ 2 A 2 = 
mꞷ 2 A 2
ꞷ = 
A = Lθ
KE = 
m 
× L 2 θ 2 , KE = 
mgLθ 2
K 1 = 
mgLθ 2
If length is doubled
K 2 = 
mg (2L)θ 2 [Here we are assuming angular amplitude is same]
= 
K 2 = 2K 1
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