A rod of weight W is supported by two parallel knife edges A and B and is in equilibrium in a horizontal position. The knives are at a distance d from each other. The centre of mass of the rod is at distance x from A. The normal reaction on A is :
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
C
equating torque about center of mass
N A x = N B (d-x)
N A + N B = mg
solving N A = 
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