In the figure shown a point object O is placed in air. A spherical boundary of radius of curvature 1.0 m separates two media. AB is principal axis. The refractive index above AB is 1.6 and below AB is 2.0. The separation between the images formed due to refraction at spherical surface is: 
Text Solution
Verified by ExpertsThe correct answer is:
A
For refraction by upper surface
= 
⇒ 
= 0.6 – 0.5 = 0.1
V 1 = 16 m
For refraction by lower surface
= 
= 1 – 0.5 = 0.5
V 2 = 
= 4m
Distance between images = (16 – 4) = 12m.
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