In the following circuit, the output Y for all possible inputs A and B is expressed by the truth table:
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
D
Gates-I and II are NOR gates.
We can simplify the gate circuit as
Here. gates-I and II are NOR gates. The output (A + B) of gate-I will be appeared as input of gate-II. The final output is
Y = A + B = A + B
This is the Boolean expression of OR gate whose truth table is given below :
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