The wave described by y = 0.25 sin (10 π π x –2 π π t), where x and y are in meter and t in second, is a wave travelling along the
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The sign between two terms in argument of sine will define its direction.
Writing the given wave equation
y = 0.25 sin (10 π π x – 2 π π t) ....(i)
The minus (–) between (10 π π x) and (2 π π t) implies that the wave is travelling along positive x direction.
Now comparing Eq. (i) with standard wave equation
y = a sin (kx – t) ...(ii)
We have
a = 0.25 m, ꞷ = 2 π π , k = 10 π π m
∴
= 2 π π
⇒ ƒ = 1 Hz
Also, λ λ =
= 0.2 m
Therefore, the wave is travelling along +ve x direction with frequency 1 Hz and wavelength 0.2 m.
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