Two trains A and B of length 400 m each are moving on two parallel tracks with a uniform speed of 
in the same direction, with A ahead of B. The driver of B decides to overtake A and accelerates by 
. If after 50 s, the guard of B just brushes past the driver of A and the original distance between them is x , then calculate value of 
?
Text Solution
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45.00
Length of each train,
A = 
B = 400m
=20m/s
Distance travelled by train A in 50 s
s A = u A xt
(As for unaccelerated motion, distance = Speed x Time)
s a = 20 x 50
= 1000m
Distance travelled by train B in 50 s, 
(As motion of train B is an accelerated motion)
= 1000+1250
= 2250 m
relative distance between the two trains =S B -Sa
= 2250-1000
= 1250m
we should subtract 2 
from it where 
is length of train so final answer will be 450 m
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