Physics Motion in a Straight Line NTA Abhiyas Question - Motion in One Dimensional MCQ (Single Correct)

A man in a balloon throws a stone downwards with a speed of 5 m s -1 with respect to the balloon which is moving upwards with a constant acceleration of 5 m s -2 . Find the velocity (in m s -1 ) of the stone relative to the man after 2 s. (Take g = 10 m s -2 )

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35

Relative velocity of stone = 5 m s -1

relative acceleration of stone = 10 + 5 = 15 m s -2

v = u + at = 5 + 15 x 2 = 35ms -1

relative velocity after t = 2s is 35 ms -1

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