Home Physics Newton's Laws of Motion NTA Abhiyas Question A block of mass m = 2 kg is placed on a plan…
Physics Newton's Laws of Motion NTA Abhiyas Question MCQ (Single Correct)

A block of mass m = 2 kg is placed on a plank of mass M = 10 kg, which is placed on a smooth horizontal plane, as shown in the figure. The coefficient of friction between the block and the plank is . If a horizontal force F is applied on the plank, then the maximum value of F for which the block and the plank move together is (g = 10 r n/s 2 )

A
50 N
B
40 N
C
120 N
D
100 N

Share this question

For Instagram sharing, use “Apps” on mobile or copy the link.

Text Solution

Verified by Experts
The correct answer is:
B

40 N

assuming no slipping between m and M This means friction between the block and plank is

Prepare Smarter with CGP Edu

Get practice questions, solutions, and test series in one place.

Write a Review

Share your experience with this question and solution.

Commentary

Send your comment, doubt, correction, or feedback to admin.

Student Reviews

What students say about this solution

No reviews yet. Be the first to write a review.

Similar Questions

Explore conceptually related problems

CG
CGP Question Assistant Question Bank + AI Help
Hi! Type your question or upload one screenshot. First I will search related questions from CGP Edu Question Bank. If none match, type YES and I will solve it with AI.
Upload only one screenshot at a time. Flow: Question Bank first → If not matched, type YES for AI solution.