A long cylindrical volume (of radius R) contains a uniformly distributed charge of density ρ. Consider a point P inside the cylindrical volume at a distance x from its axis as shown in the figure. Here x can be more than or less than R. Electric field at point P is:
A
if ;fn x < R
B
if ;fn x < R
C
if ;fn x > R
D
if ;fn x > R
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(a, d)
Case (i) x < R
Let a Gaussian surface is a cylinder of radius r and length equal to given cylinder
and 
are parallel to each other, so: 
= 
= 
⇒ 
= E 
= E. 2πr L
⇒ E = 
(ii) x 
R: Again by 
= 
= E 
⇒ 
= E (2πr) L ⇒ E = 
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