A steel ball of mass 0.5 kg is dropped from a height of 4 m on to a horizontal heavy steel slab. The ball strike the slab and rebounds to its original height. (take g = 10 m/sec 2 )
Text Solution
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CHECK THE SOLUTION.
4 
Ns 2000 
N
Sol. v = 
= 
= 
J = Δ P = 2mv = 2 × 
× 
⇒ J = 
N-s
∫ N dt = ∫ dP
N × 2 × 10 –3 = 
∴ N = 
×10 3 N
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