The de Broglie wavelength of a molecule in a gas at room temperature (300 K) is 
. If the temperature of the gas is increased to 600 K, then the de Broglie wavelength of the same gas molecule becomes
A
B
C
D
2 
Text Solution
Verified by ExpertsThe correct answer is:
C
The root mean squared velocity of a gas is given by
Let T 1 = 300 K
T 2 = 600 K
Taking velocity ratios at the given temperatures,
The de Broglie wavelength is given by 
. So,
The ratio of the wavelengths is
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