A beam of light consisting of two wavelengths 7000 
and 5500 
is used to obtain interference pattern in Young's double slit experiment. The distance between the slits is 2. 5 mm and the distance between the plane of slits and the screen is 150 cm. The least distance from the central fringe, where the bright fringes due to both the wavelengths coincide, is n x 10 -5 m. The value of n is_____.
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(462)
The given data is
d= 2.5 x10 -3 m
D = 1.5m
The path difference is given by
7n = 5. 5 m
14n = 11 m 
n = 11 and m = 14
The formula for the distance of a bright fringe is
= 46. 2 x 10 -4 = 462 x 10 -5 It is given that
n x 10
-5 = 462 x 10 -5
n = 462
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