A man, the surface area of whose skin is 2m 2 , is sitting in a room where the air temperature is 20°C. If the skin temperature is 28°C. Find the net rate at which his body loses heat. [Take the emissivity of skin 0.97 and stephen’s constant = 5.67 × 10 –8 W/m 2 – K 4
Text Solution
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CHECK THE SOLUTION.
(92.2 W)
e σ A(T 4 – T 4 surroundings ) = 0.97 × 5.67 × 10 – 8 .2 (301 4 – 293 4 ) = 92.2 W
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