A tube of 1 mm bore is dipped into a vessel containing a liquid of density 0.8 g/cm 3 , surface tension 30 dyne/cm and angle of contact zero. Calculate the length which the liquid will occupy in the tube when the tube is held
Text Solution
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[ 1.53 cm, 1.77 cm]
Sol.
for vertically placed tube:
h = 
where r = 0.5 mm.
so, h = 
= 1.51 cm.
for inclined tube:
we know that
P A = P 0
P C = P 0
and P B = P 0 – 
where P 0 = atmospheric pressure
Equating pressure of the level in liquid: we get
P 0 – 
+ (h ’ cos 30º) ρ g = P 0 .
⇒ h ’ = 
= 
= 
where h was found in part so h’ = 
= 1.749 cm.
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