A soap film is stretched over a rectangular vertical wire frame as shown in the figure, what forces hold section abcd in equilibrium?
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The FBD of part abcd is as shown. The surface tension forces F ab upward; F cd downward and weight (w)
of part abcd are holding the part abcd in equilibrium.
F ab – F cd = w.
Clearly F ab > F cd and this is due to difference in concentration of soap solution in film.
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