A particle performing SHM with amplitude 10cm. At What distance from mean position the kinetic energy of the particle is thrice of its potential energy?
Text Solution
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(± 5 cm)
According to question
mv 2 = 3 × 
mꞷ 2 x 2
⇒ 
mꞷ 2 (A 2 – x 2 ) = 
mꞷ 2 x 2
⇒ A 2 = 4x 2
⇒ x = ± 
= ± 
= ± 5 cm.
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