A particle rests in equilibrium under two forces of repulsion whose centers are at distance of a and b from the particle. The forces vary as the cube of the distance. The forces per unit mass are k and k' respectively. If the particle be slightly displaced towards one of them the motion is simple harmonic with the time period equal to
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
D
C 1 a 3 = C 2 b 3
F rs = C 1 (a – x) 3 – C 2 (b + x) 3
= C 1 a 3 
– C 2 b 3 
= – 3(C 1 a 2 + C 2 b 2 )x
time period = 
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