Assuming all the surfaces to be smooth, if the time period of motion of the ball is N × 10 –1 sec then find N. Neglect the small effect of bend near the bottom. (g = 10m/s 2 )
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(16)
S = 
, a = g sin 30, h = 20 cm, u = 0
S = ut + 
⇒ t = 
= 
= 0.4
v = 0 + (g sin30) (0.4) = 2
For BC max height reached by the particle will be same as h = 20 cm
(by energy conservation)
and for BA and BC t = 0.4
Total time period = 0.4 × 4 = 1.6 second = 16×10 –1 sec
∴ N= 16
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