In the figure shown mass 2m is at rest and in equilibrium. A particle of mass m is released from height 
from plate. The particle sticks to the plate. Neglecting the duration of collision. Starting from the time when the particle sticks to plate to the time when the spring is in maximum compression for the first time is 
then find a.
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(3)
Velocity of the particle just before collision
u = 
u = 
Now it collides with the plate.
Now just after collision velocity of system of plate + particle
mu = 3mv
⇒ V = 
= g 
Now system perform’s SHM with time period T = 2 π 
and mean position as 
distance below the point of collision.
Let the equation of motion be.
y = A sin (ꞷt + φ )
for t = 0, y = mg/K
= A sin φ ...
Now for amplitude
V = ꞷ 
g 
= 
= A 2 – 
A = 
...
By &
T = 
x = 
to l x = 0
⇒ t = 
x = 0 to x = A
⇒ t = T/4
total time = 
= 
∴ a = 3
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems