There are identical small holes of area of cross-section a on the opposite sides of a tank containing a liquid of density ρ . The difference in height between the holes is h. Tank is resting on a smooth horizontal surface. Horizontal force which will have to be applied on the tank to keep it in equilibrium is –
A
gh ρ a
B
C
2 ρ agh
D
Text Solution
Verified by ExpertsThe correct answer is:
C
Thrust force
F = F 1 – F 2 = ρ a ν 1 2 – ρ a ν 2 2
= ρ a (2gh 1 ) – ρ a (2gh 2 )
= 2 ρ ag (h 1 – h 2 )
=2 ρ agh
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