A string of length 1m is fixed at one end and carries a mass of 100 g at the other end. The string makes 2/ π π revolutions per second around the vertical axis through the fixed end. If angle of inclination of the string with the vertical is cos -1 5/8, the linear velocity of the mass is nearly
Text Solution
Verified by ExpertsThe correct answer is:
C
Using u = r ω ω = r × 2 π π f
= 1 sin θ θ × 2 π π f, we get
( Q r = 1 sin θ θ )
u = 1 × 0.78 × 2 π π × 
= 3.12 ms -1
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