Trajectories of two projectiles are shown in the figure. Let T 1 and T 2 be the time of flights and u 1 and u 2 be their speeds of projection. Then -
Text Solution
Verified by ExpertsThe correct answer is:
D
Both projectiles have same height
∴ (u sin θ ) 1 = (u sin θ ) 2 ⇒ T 1 = T 2
But range is more for 2 nd body.
∴ (u cos θ ) 2 > (u cos θ ) 1 ⇒ u 2 > u 1
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