Published by:
CGP EDU Academic Team
Published on: September 12, 2026
Two runners’ starts simultaneously from the same point one a circular 200 m track in the same direction. Their speeds are 6.2 ms -1 and 5.5 ms -1 . How far from the starting point the faster will overcome the slower?
Text Solution
Verified by ExpertsThe correct answer is:
B
200 = (6.2 – 5.5) t or t = 285.714 s
s = (6.2 × 285.714) = 1770m (faster), 1770 – 8 × 200 = 170
Thus 170 m away from the starting point along the track in the direction of run.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A body of mass \(\pi\pi\) hangs at one end of a string of length l , the other end of which is fixe…
The tension in the string revolving in a vertical circle with a mass m at the end which is at the l…
A stone of mass m is tied to a string and is moved in a vertical circle of radius r making n revolu…
A tube of length l is filled completely with an incompressible liquid of mass \(\mathbf{M}\) and cl…
The kinetic energy k of a particle moving along a circle of radius R depends on the distance covere…
A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/sec . A…