In a transition to a state of excitation energy 10.19ev, a hydrogen atom emits a 4890 Å photon. The Binding energy of the initial state is -
Text Solution
Verified by ExpertsThe correct answer is:
D
Energy of emitted photon is
E =
= 2.54 ev
The excitation energy is the energy to excite the atom to a level above the ground state. Therefore, the energy level is
E = – 13.6 + 10.19 = – 3.41 eV
Photon arises from transition between energy state such that
E i – E f = h ν = 2.54 eV
E i = 2.54 + E f
E i = 2.54 + (E) = 2.54 – 3.41eV = – 0.87eV
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