Published by:
CGP EDU Academic Team
Published on: September 12, 2026
Nearly 10% of the power of a 110 W light bulb is converted to visible radiation. The change in average intensities of visible radiation, at a distance of 1 m from the bulb to a distance of 5 m i is a x 10 -2 W/m 2 . The value of 'a' will be
Text Solution
Verified by ExpertsThe correct answer is:
84
(84)
Sol. P ’ = 10% of 110 W
=11W
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