A body is thrown vertically upwards. If air resistance is t…

Physics Motion in a Straight Line Motion Under Gravity Single Correct MCQ

Published on: September 13, 2026

A body is thrown vertically upwards. If air resistance is to be taken into account, then the time during which the body rises is

Equal to the time of fall

Less than the time of fall

Greater than the time of fall

Twice the time of fall

Text Solution

Verified by Experts

The correct answer is:

Let the initial velocity of ball be u

Time of rise \(\ell_1 = \frac{v}{g+o}\) and height reached \(-\frac{u^{c}}{Z(g + \rho)}\)

Time of fall t_2 is given by

\(\frac{1}{2}(g \cdot a)t^{2} - \frac{u^{2}}{2(g - a)}\)

\(\rightarrow t_{2} \quad \frac{u}{\sqrt{(g+a)(g-a)}} \quad \frac{u}{(g+a)} \sqrt{\frac{g-a}{g+a}}\)

\vec{F} \Sigma_{x} > \Sigma_{1} because \(\frac{1}{g+a} > \frac{1}{g-a}\)

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