A ball is projected upwards from a height \hat{h} above the…

Physics Motion in a Straight Line Mix Single Correct MCQ

Published on: September 12, 2026

A ball is projected upwards from a height \hat{h} above the surface of the earth with velocity \vec{v} . The time at which the ball strikes the ground is

\(\frac{v}{g} + \frac{2hg}{\sqrt{2}}\)

\(\frac{\nu}{g} \left| 1 - \frac{i}{\nu} + \frac{2fr}{g} \right|\)

\(\frac{v}{g} \left| 1 + \frac{l}{\eta} + \frac{2gh}{v^2} \right|\)

\(\frac{\nu}{g} \left| 1 + \frac{r}{\nu} \nu^{2} + \frac{2g}{h} \right|\)

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The correct answer is:

Since direction of v is opposite to the direction of g and h so from equation of motion

\(h = -Vt + \frac{1}{2}gt^{2}\)

g t^{2} - 2 v t + 2 l = 0

\(\Rightarrow t = \frac{-2v \pm \sqrt{4v^{2} + 8gh}}{2g}\)

\(t = \frac{v}{g} \cdot \left| 1 + \sqrt{1 + \frac{2gh}{v^{2}}} \right|\)

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