Home Physics Motion in a Straight Line Mix A small block slides without friction down a…
Physics Motion in a Straight Line Mix Single Correct MCQ
Published on: September 12, 2026

A small block slides without friction down an inclined plane starting from rest. Let S^n be the distance travelled from time t = n - 1 to t = n. Then \(\begin{cases} 5, \\ 5_{x-1} \end{cases}\) is

A
\(\frac{2n - 1}{2n}\)
B
\(\frac{2n+1}{2n-1}\)
C
\(\frac{2n - 1}{2n + 1}\)
D
\(\frac{2n}{2n+1}\)

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Text Solution

Verified by Experts
The correct answer is:
A
To find the distance traveled by the block down the inclined plane as a function of time, we can use the equations of motion. As the block slides down, its motion can be described by the linear acceleration caused by gravity.
Step 1: The acceleration of the block down the incline is given by:
$$ a = g imes ext{sin}(\theta) $$
where $g$ is the acceleration due to gravity and $\theta$ is the angle of inclination.
Step 2: The distance traveled by an object starting from rest is given by the equation:
$$ s = \frac{1}{2} a t^2 $$
Step 3: Substitute the expression for acceleration into the distance formula:
$$ s = \frac{1}{2} (g \times \text{sin}(\theta)) t^2 $$
This gives us a quadratic function of time, confirming that option A is correct for the description of distance $s$ as time $t$ increases.

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