The acceleration-time graph of a body is shown below
.
The most probable velocity-time graph of the body is
Text Solution
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From given 0 - t graph it is clear that acceleration is increasing at constant rate
\(\frac{d\theta}{dx} - k\) (constant) ⇒ ⇒ \(\sigma = kt\) (by integration)
⇒ ⇒ \(\frac{dv}{dt} = kt\) ⇒ ⇒ \(\frac{d\nu}{dt} = k t \alpha t\)
⇒ ⇒ \(\int d\mathbf{r} = k \int r \, dr\) ⇒ ⇒ \(v = \frac{kt^2}{2}\)
i.e. v is dependent on time parabolically and parabola is symmetric about v -axis.
and suddenly acceleration becomes zero. i.e . velocity becomes constant.
Hence is most probable graph.
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