A car A is travelling on a straight level road with a uniform speed of 60 km/h. It is followed by another car B which is moving with a speed of 70 km/h. When the distance between them is 2.5 km , the car B is given a deceleration of 20 \(\mathrm{km/h^{2}}.\) After how much time will B catch up with A
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Let car B catches, car A after ‘ t ’ sec, then
\(60t + 2.5 - 70t - \frac{1}{2} \times 20 \times t^{2}\)
⇒ ⇒ 10t^{2} - 10t + 2.5 = 0 ⇒ ⇒ t^{2} - t + 0.25 = 0
\(\mathrm{H - O - H}\) \(t = \frac{1}{2} \times \sqrt{1^2 - 4 \times (0.25)} = \frac{1}{2} hr\)
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